If it's not what You are looking for type in the equation solver your own equation and let us solve it.
8x^2+2x^2+7x=
We move all terms to the left:
8x^2+2x^2+7x-()=0
We add all the numbers together, and all the variables
10x^2+7x=0
a = 10; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·10·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*10}=\frac{-14}{20} =-7/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*10}=\frac{0}{20} =0 $
| 3x-30x-25=-2 | | −3w−4=w+3 | | 9+h/4=12 | | 2=v-94/2 | | 3x+28=52 | | -1÷3*u=10 | | 5b^2−20b=b^2. | | 1/2(-x-6)=-1/2x-3 | | -19=-4m+5 | | 17-9x=124 | | 2c−3=26−c+7c | | 1/2(-x-6)=-1/2x+8 | | -5(2g-3)-5g=-45 | | 12-(3n-7)+8n=-2(4-3n) | | 5(x)=120 | | 3q+8=41 | | —6=0.75(r—12) | | 2x+10=4(x-3) | | 7(2x-3)=7(x-3) | | y/3+3=8 | | 7(2x-3)=2(7x+5) | | 20.6+2.1n=8.2n | | 144=-12b-60 | | (x-4)^2=2x | | 8h+5=53 | | 0+x+4x+7x=180 | | 13/4(12a+8)=27.6 | | 4/3k=36 | | 24=a/3-9 | | 13x+44=104 | | –2j=–10−j | | 7x+44=71 |